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Mathematics 05802.8

Functions

Function notation, composite and inverse functions.

Learning objectives

What you need to be able to do

Teacher-mapped phrasing — check against the official Cambridge syllabus for exact wording.

  • 2.8.1Use function notation and find composite and inverse functions.Supplement

5 minute read

Functions

Notation

f(x) = 3x + 1 is a rule. f(2) means substitute 2 for x, giving 7. The letter in the bracket is only a placeholder.

Composite functions

fg(x) means "do g first, then f" — the function nearer x acts first. With f(x) = 2x + 1 and g(x) = x²:

  • fg(x) = f(x²) = 2x² + 1
  • gf(x) = g(2x + 1) = (2x + 1)²

These differ, so order matters.

Inverse functions

f⁻¹(x) reverses f. To find it:

  1. Write y = f(x).
  2. Swap x and y.
  3. Rearrange to make y the subject.

For f(x) = 3x − 4: y = 3x − 4 → x = 3y − 4 → y = (x + 4)/3.

Checking

ff⁻¹(x) = x always. Substituting your inverse back is the quickest way to confirm it, and takes one line.

Think of it like this

A function is a machine and its inverse is the same machine run backwards. Composite functions are two machines in a line — and reversing the order of the machines generally changes what comes out.

Worked examples

Method, step by step

Given f(x) = 2x − 3 and g(x) = x + 5, find gf(x) and f⁻¹(x).

  1. 1gf(x) means f acts first: f(x) = 2x − 3.
  2. 2Then apply g: g(2x − 3) = (2x − 3) + 5 = 2x + 2.
  3. 3For the inverse, write y = 2x − 3 and swap: x = 2y − 3.
  4. 4Rearrange: 2y = x + 3, so y = (x + 3)/2.

gf(x) = 2x + 2 and f⁻¹(x) = (x + 3)/2

Common misconceptions

  • Reading `fg(x)` as "f first". The inner function acts first.
  • Treating `f⁻¹(x)` as `1/f(x)`. The −1 denotes the inverse, not a reciprocal.
  • Forgetting to swap x and y when finding an inverse, which produces the original function rearranged rather than its inverse.

In the exam

  • Write out the substitution explicitly, e.g. `fg(x) = f(x²)`, before simplifying — it earns method marks and prevents order errors.
  • Verify any inverse with `ff⁻¹(x)`; if it does not simplify to x, something is wrong.