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Mathematics 05805.1

Area, volume and surface area

The standard formulae, and choosing the right one.

Learning objectives

What you need to be able to do

Teacher-mapped phrasing — check against the official Cambridge syllabus for exact wording.

  • 5.1.1Calculate perimeter and area of common shapes including circles and compound shapes.
  • 5.1.2Calculate surface area and volume of prisms, cylinders, cones and spheres.

6 minute read

Area, volume and surface area

Areas worth knowing cold

  • Rectangle: length × width
  • Triangle: ½ × base × height (perpendicular height, not the slant side)
  • Parallelogram: base × perpendicular height
  • Trapezium: ½(a + b) × h
  • Circle: A = πr², circumference C = 2πr or πd

Volumes

  • Prism (constant cross-section): area of cross-section × length
  • Cylinder: πr²h
  • Cone: ⅓πr²h
  • Sphere: 4/3 πr³
  • Pyramid: ⅓ × base area × height

The cone and pyramid both carry the ⅓, which is the factor most often dropped.

Surface areas

  • Cylinder (closed): 2πr² + 2πrh — two circles plus the curved surface, which unrolls into a rectangle of width 2πr and height h.
  • Cone: πr² + πrl, where l is the slant height, not the vertical height.
  • Sphere: 4πr²

If a question says "open cylinder" or "no lid", leave out one or both circles — read carefully.

Compound shapes

Split into standard shapes, calculate each, then add or subtract. Label each part so the method is visible to the examiner.

Units — a reliable source of lost marks

Area is in square units, volume in cubic units. When converting, remember 1 m² = 10 000 cm² and 1 m³ = 1 000 000 cm³, because the conversion factor is squared or cubed.

Think of it like this

The curved surface of a cylinder is a label peeled off a tin: it unrolls into a rectangle whose width is the circumference. That is exactly where `2πrh` comes from, so the formula need not be memorised blindly.

Worked examples

Method, step by step

A cylinder has radius 5 cm and height 12 cm. Find its volume and total surface area, to 3 significant figures.

  1. 1Volume = πr²h = π × 5² × 12 = 300π ≈ 942.48 cm³.
  2. 2Surface area = 2πr² + 2πrh.
  3. 32π(5²) = 50π and 2π(5)(12) = 120π.
  4. 4Total = 170π ≈ 534.07 cm².

Volume ≈ 942 cm³; surface area ≈ 534 cm²

Common misconceptions

  • Using the slant height in the cone **volume** formula. Volume uses the perpendicular height h; the slant height l belongs in the curved surface area.
  • Converting areas with a linear factor — 1 m² is 10 000 cm², not 100.
  • Forgetting the ⅓ in cone and pyramid volumes, which triples the answer.

In the exam

  • Write the formula down before substituting. It earns method marks even if the arithmetic later goes wrong.
  • Keep π in your calculator to full precision and round only at the end, unless asked to leave the answer in terms of π.